Create URI in a SPARQL CONSTRUCT query

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#1

Hi,

Is there a simple way to create a new URI in a CONSTRUCT query ? For example by concatenating variables with a prefix ? (This new URI is necessary to create a new individual)

#2

There's a function called URI() that converts a string to a URI

CONSTRUCT { ?s a :Duck . }
WHERE {
    :DuckTarget :someProperty ?stringValuedField
    BIND (URI(CONCAT("http://ducks.example.com/aDuck/",?stringValuedField)) AS ?s)
}

pretty simple...

#3

Virtuoso uses custom syntax extension --- an expression can be enclosed into backquotes and placed directly into group pattern or in constructor template instead of a plain variable. Plain-old LISP style. In your case it could be

CONSTRUCT { `iri(bif:concat("http://ducks.example.com/aDuck/",?stringValuedField))` a :Duck . }
WHERE { :DuckTarget :someProperty ?stringValuedField }